修正了矩阵运算
This commit is contained in:
parent
e8404e1f9d
commit
278684310d
|
@ -57,18 +57,10 @@ def solve_equation(eq):
|
|||
matrix = np.mat(matrix, int)
|
||||
# 求解线性方程组
|
||||
try:
|
||||
result = np.linalg.solve(matrix, constant).tolist()
|
||||
except np.linalg.LinAlgError:
|
||||
# 将常数项取负,插入到矩阵的最后一列
|
||||
constant = [-x for x in constant]
|
||||
matrix = np.insert(matrix, matrix.shape[1], constant, axis=1)
|
||||
# 再次尝试求解
|
||||
try:
|
||||
constant = np.zeros(matrix.shape[0], int)
|
||||
result = sp.linalg.solve(matrix, constant).tolist()
|
||||
except Exception as e:
|
||||
print('无法配平' + str(e))
|
||||
return None
|
||||
result = sp.optimize.lsq_linear(matrix, constant, bounds=(0, None)).x.tolist()
|
||||
except ValueError:
|
||||
print('无法配平')
|
||||
return None
|
||||
|
||||
# 将结果写入化学方程式,最后一个生成物的系数需要计算得到
|
||||
last_substance = eq['right'][-1]
|
||||
|
@ -76,7 +68,6 @@ def solve_equation(eq):
|
|||
# 计算除最后一种生成物外的所有生成物包含last_atom的系数之和
|
||||
sum_ = 0
|
||||
index = 0
|
||||
print(result)
|
||||
for each in eq['left']:
|
||||
for atom in each['atoms']:
|
||||
if last_atom in atom:
|
||||
|
|
Loading…
Reference in New Issue