修正了parser 矩阵运算还不完善
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@ -53,15 +53,21 @@ def solve_equation(eq):
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row.append(0)
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# 取出row中的最后一个元素,反转后加入常数项
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constant.append(-row.pop())
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matrix.append(row)
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matrix = np.mat(matrix, int)
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print(matrix)
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print(constant)
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# 求解线性方程组
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try:
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result = np.linalg.solve(matrix, constant).tolist()
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except np.linalg.LinAlgError:
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# 将常数项取负,插入到矩阵的最后一列
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constant = [-x for x in constant]
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matrix = np.insert(matrix, matrix.shape[1], constant, axis=1)
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# 再次尝试求解
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try:
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constant = np.zeros(matrix.shape[0], int)
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result = sp.linalg.solve(matrix, constant).tolist()
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except Exception as e:
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print(e.args[0])
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print('无解')
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print('无法配平' + str(e))
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return None
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# 将结果写入化学方程式,最后一个生成物的系数需要计算得到
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@ -70,6 +76,7 @@ def solve_equation(eq):
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# 计算除最后一种生成物外的所有生成物包含last_atom的系数之和
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sum_ = 0
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index = 0
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print(result)
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for each in eq['left']:
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for atom in each['atoms']:
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if last_atom in atom:
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5
main.py
5
main.py
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@ -10,9 +10,12 @@ import equation_solver
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if __name__ == '__main__':
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while True:
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eq = input('请输入化学方程式:')
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if eq == 'exit':
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break
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try:
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eq = parser.parse_equation(eq)
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equation_solver.solve_equation(eq)
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eq = equation_solver.solve_equation(eq)
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if eq is not None:
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print('化学方程式:', parser.format_equation(eq))
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except Exception as e:
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print(e.args[0])
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35
parser.py
35
parser.py
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@ -49,21 +49,30 @@ def parse_atomic_clusters(atomic_clusters):
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"""
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将原子团转化为字典
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:param atomic_clusters: 经过parse_molecule处理后的原子团
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如(ClO)2->['(', 'Cl', 'O', ')2']
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如(ClO)2->['(', 'Cl', 'O', ')', '2']
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:return: 原子团的字典表示
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"""
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# 去除首括号
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atomic_clusters = atomic_clusters[1:]
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# 去除尾括号,解析尾括号后的数值作为原子团系数
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if atomic_clusters[-1][-1].isdigit():
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coefficient = int(atomic_clusters[-1][-1])
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atomic_clusters = atomic_clusters[:-1]
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if atomic_clusters[-1].isdigit():
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coefficient = int(atomic_clusters[-1])
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atomic_clusters = atomic_clusters[:-2]
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elif atomic_clusters[-1] == ')':
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coefficient = 1
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else:
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raise ValueError('无效的原子团系数')
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# 解析原子团
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atoms = []
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for i in range(len(atomic_clusters)):
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if atomic_clusters[i].isdigit():
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while atomic_clusters[i - 1] == '':
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i -= 1
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if i == 0:
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raise ValueError('系数错误')
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atomic_clusters[i - 1] += atomic_clusters[i]
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atomic_clusters[i] = ''
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atomic_clusters = [atom for atom in atomic_clusters if atom != '']
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for atom in atomic_clusters:
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atoms.append(parse_atom(atom))
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return {
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@ -86,27 +95,30 @@ def parse_molecule(molecule):
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:param molecule: 化学式
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:return: 化学式的字典表示
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"""
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pretty_name = ''
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if molecule[0].isdigit():
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coefficient = int(molecule[0])
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pretty_name = molecule = molecule[1:]
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else:
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coefficient = 1
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pretty_name = molecule
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# 以大写字母为分隔符,分割化学式
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molecule = re.split(r'([A-Z][a-z]*)', molecule)
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# 以大写字母和括号为分隔符,分割化学式
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molecule = re.split('([A-Z][a-z]*|\(|\))', molecule)
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molecule = [i for i in molecule if i != '']
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# 将原子团提取出来单独处理
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atomic_clusters = []
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for i in range(len(molecule)):
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if molecule[i] == '(':
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j = i + 1
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while molecule[j][0] != ')':
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# 当molecule内不包含右括号
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while ')' not in molecule[j]:
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j += 1
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if j == len(molecule):
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raise ValueError('括号不匹配')
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for k in range(i, j + 1):
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atomic_clusters.append(molecule[k])
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if j + 1 < len(molecule) and molecule[j + 1].isdigit():
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atomic_clusters.append(molecule[j + 1])
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molecule[j + 1] = ''
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for k in range(i, j + 1):
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molecule[k] = ''
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# 如果出现单个数字,说明该数字是系数,将其追加到上一个原子/原子团(非空字符串)的后面
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@ -169,6 +181,7 @@ def format_molecule(molecule):
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else:
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return molecule['pretty_name']
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def format_equation(eq):
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"""
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将化学方程式的字典表示转化为字符串,需要包含系数
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@ -180,3 +193,9 @@ def format_equation(eq):
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left = [format_molecule(molecule) for molecule in left]
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right = [format_molecule(molecule) for molecule in right]
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return ' + '.join(left) + ' => ' + ' + '.join(right)
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if __name__ == '__main__':
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eq = input('测试parser:请输入分子式:')
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parsed_eq = parse_molecule(eq)
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print('解析结果:', parsed_eq)
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